Math s.1 (10點!!)
2012-08-06 12:55 am
1)It is given that x=40 and y=100. If x and y are increased by 8% and 15% respectively, find the percentage increase in their product.
回答 (2)
2012-08-06 3:06 am
✔ 最佳答案
Original value of xy = 40x100 = 4000New value of xy = x(1+8%)y(1+15%) = 40x1.08x100x1.15 = 4968
So, the percentage increase = (4968-4000)/4000x100% = 24.2%
參考: me
2012-08-07 7:02 am
The percentage increase in their product is:
[x(1+8%) * y(1+15%) -xy]/xy * 100%
=xy(1.08*1.15-1)/xy *100%
=24.2%
(Actually the percentage increase in their product has nothing to do with the values of x and y.).
[x(1+8%) * y(1+15%) -xy]/xy * 100%
=xy(1.08*1.15-1)/xy *100%
=24.2%
(Actually the percentage increase in their product has nothing to do with the values of x and y.).
收錄日期: 2021-04-13 18:53:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120805000051KK00449