Identities
find the value of A and B
(a)8x-3=Ax+B
(b)(6x+1)(6x-1)=Ax^2+B
(c)(x-3)^2=x^2+Ax+B
(d)Ax^2-6=5x^2+Bx-6
(e)(2x-3)(x+6)+A=2x^2+Bx
有睇吾明的地方可以問!!!
知道答案的plz help!!!!!
中二數學問題求幫忙(5點)
2012-08-01 7:48 pm
回答 (1)
2012-08-04 2:36 am
✔ 最佳答案
(a)8x - 3 = Ax + B
8x + (-3) = Ax + B
∴ A = 8 , B = - 3
(b)
(6x + 1)(6x - 1) = Ax² + B
36x² - 1 = Ax² + B
∴ A = 36 , B = - 1
(c)
(x - 3)² = x² + Ax + B
x² - 6x + 9 = x² + Ax + B
∴ A = - 6 , B = 9
(d)
Ax² - 6 = 5x² + Bx - 6
Ax² + 0x - 6 = 5x² + Bx - 6
∴ A = 5 , B = 0
(e)
(2x-3) (x+6) + A = 2x² + Bx
2x² + 9x - 18 + A = 2x² + Bx
2x² + 9x + (A - 18) = 2x² + Bx + 0
∴ B = 9
A - 18 = 0
A = 18
收錄日期: 2021-04-21 22:24:44
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