數學題!急!10點
2012-07-31 7:31 am
a submarine stays at 150 m below water surface . it first ascends vertically to a position of 42 m below water surface and then descends vertically to a position of 135 m below the water surface . if -60 denotes 60 m the water surface , find the total distance travelled by submarine?
回答 (1)
2012-07-31 7:49 am
✔ 最佳答案
It first ascends vertically to a position of 42 m below water surface :- 42 - (- 150) = 108 m travelled.
And then descends vertically to a position of 135 m below the water surface :
- 42 - (- 135) = 93 m travelled.
∴ The total distance travelled by submarine = 108 + 93 = 201 m.
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https://hk.answers.yahoo.com/question/index?qid=20120730000051KK00961