✔ 最佳答案
1)
∠CAB = (1/2)∠COB (∠at centre twice ∠ at ☉ce)
Let M be the mid point of BC , then OM ⊥ BC and EM ⊥ BC since EM is the height of isos.△ BEC , so EOM is a straight line
So ∠BOM = (1/2)∠COB =∠CAB ,
therefore A,E ,O AND B ARE CONCYCLIC. (ext.∠= int. opp.∠)