x^2-2x-3=0 is given.
hence,or otherwise,solve the following equation.
1/(x^2(x-2)^2)+(2/x(x-2))-3=0
maths question
2012-07-30 4:03 am
回答 (1)
2012-08-05 3:27 am
✔ 最佳答案
1/(x²(x-2)²) + 2/(x(x-2)) - 3 = 0 Let -y be 1/(x(x-2)) , theny² - 2y - 3 = 0
(y + 1)(y - 3) = 0
y = - 1 or y = 31/(x(x-2)) = 1
x² - 2x - 1 = 0
x = 1 ± √2or1/(x(x-2)) = - 3
3x² - 6x + 1 = 0
x = (3 ± √6)/3
收錄日期: 2021-04-21 22:25:58
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