factorize (x+a)^2-9(x-a)^2
thanks for replying
factorize
2012-07-28 5:24 am
回答 (3)
2012-07-28 6:10 am
✔ 最佳答案
= (x + a)² - 9(x – a)²= (x + a)² -[3(x – a)]²= [(x + a) - 3(x – a)][(x + a) + 3(x – a)]= (- 2x + 4a)(4x – 2a)= 4(2a - x)(2x – a) I HOPE THIS CAN HELP YOU! ^_^
參考: My Maths World
2012-07-28 7:21 am
(x+a)^2-9(x-a)^2
=[(x+a)+3(x-a)][(x+a)-3(x-a)]
=(x+a+3x-3a)(x+a-3x+3a)
=(4x-2a)(-2x+4a)
=4(2x-a)(-x+2a)
=[(x+a)+3(x-a)][(x+a)-3(x-a)]
=(x+a+3x-3a)(x+a-3x+3a)
=(4x-2a)(-2x+4a)
=4(2x-a)(-x+2a)
2012-07-28 6:11 am
(x+a)^2 - 9(x-a)^2
= (x+a)^2 - [3(x-a)]^2
= (x+a+3(x-a))(x+a-3(x-a))
= (x+a + 3x - 3a)(x+a - 3x +3a)
= ( 4x - 2a) ( -2x + 4a)
= - 4(2x - a)( x - 2a)
= 4(a-2x)(x-2a)
= (x+a)^2 - [3(x-a)]^2
= (x+a+3(x-a))(x+a-3(x-a))
= (x+a + 3x - 3a)(x+a - 3x +3a)
= ( 4x - 2a) ( -2x + 4a)
= - 4(2x - a)( x - 2a)
= 4(a-2x)(x-2a)
參考: me
收錄日期: 2021-04-13 18:51:53
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