✔ 最佳答案
Let O be the centre of the semicircle.
then ∠AOC = π - π/6 - π/6 = 2π/3.The shaded part + △AOC = sector AOC
The shaded part + (1/2) OA OC sin∠AOC = (1/2)OA²∠AOC
The shaded part + (1/2)(12/2)(12/2) sin(2π/3) = (1/2)(12/2)²(2π/3)
The shaded part + 18 √3/2 = 12π
The shaded part = 12π - 9√3 = 22.11cm²