1. integrate [(x-2) / (3x+1)^2]dx from 0 to 1
2. integrate [(2x+3) / (4x^2+1)]dx from (-1/2) to ((sqrt3)/2)
3. integrate [(2x-1) / (x+1)]dx from 0 to 2
收錄日期: 2021-04-13 18:51:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120727000051KK00011