簡單多項式F.1

This is F.1 maths??!!!

2012-07-22 16:37:02 補充：
Can I use remainder theorem?

2012-07-22 21:56:12 補充：
a) (x+1)(x+2)(x+3)=(x²+3x+2)(x+3)=x³+6x²+11x+6 b) Let x+1 be the first number.(x+1)(x+2)(x+3)=1716x³+6x²+11x+6=1716x³+6x²+11x-1710=0∵ 10³+6×10²+11×10-1710=0 <-(Choice of x include∵ 10³+6×10²+11×10-1710=0 <-(all factor of 1710)∴ x-10 is a factor of x³+6x²+11x-1710 -----_______x²_+16x + 171x-10) x³ + 6x² + 11x - 1710------x³ -10x²_____________----------16x² + 11x - 1710----------16x² -160x_______----------------171x - 1710----------------171x - 1710∴ x³+6x²+11x-1710=(x-10)(x²+16x+171)=0x-10=0 OR x²+16x+171=0(rej. as 16²-171<0x-10=0 OR x²+16x+171=0 (, no real solution)∴ x=10i.e. The 3 integer are 11, 12, 13. I HOPE THIS CAN HELPYOU!~ ^_^

好呀......................