MQ32 --- Logarithm

我想問u同v有冇關係???

2012-07-23 15:13:47 補充：
-log_u(v) = log_u(1/v) or log_(1/u)(v)

2012-07-23 20:57:18 補充：
http://latex.codecogs.com/gif.latex?\begin{align*}%20log_u^{-1}v%20&=k%20\\%20v&=%20log_uk\\%20u^v&=k%20\\%20\therefore%20log_u^{-1}v%20&=u^v%20\\%20\end{align*}


log⁻¹ᵤv = u^v

2012-07-25 22:31:57 補充：
sorry= =

\begin{align*}
(log_uv)^{-1} &=\frac{1}{log_uv} \\
&= \frac{logu}{logv}\\
&= log_vu\\
\end{align*}

log⁻¹ᵤv = log_v(u)

cannot see