a.maths trigo

2012-07-22 4:03 am
Let f(x) = 2 sin x - x for 0 ≤ x ≤ π.
Find the greatest and least values of f(x).
更新1:

請問唔用f'(x)計唔計到啊??:)

回答 (2)

2012-07-23 6:56 pm
✔ 最佳答案
f(x) = 2 sin x - x
f '(x) = 2 cos x - 1
when f '(x) = 0, x = π/3

f(0) = 2 sin 0 - 0 = 0
f(π) = 2 sin π - π = -π
f(π/3) = 2 sin (π/3) - (π/3) = (3√3 - π)/3

thus the greatest value is (3√3 - π)/3,
the least value is -π

why don't use f '(x)? it is the simpliest way to do!
參考: knowledge
2012-07-22 4:21 pm
The greatest value of f(x) = √3 - π/3 when x = π/3

The least value of f(x) = - π when x = π over the given 0<= x <= π


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