✔ 最佳答案
22)a) q = 2p(6 - p) + p(6 - 2p) = 12p - 2p² + 6p - 2p² = 18p - 4p²b) 18p - 4p² = 6²/2 ⇒ 2p² - 9p + 9 = (p - 3)(2p - 3) = 0 ⇒ p = 3/2 or 3 (rej.)c) q = 18p - 4p² = 81/4 - (2p - 9/2)²; Max. of q = 81/4 when2p - 9/2 = 0, p = 9/4 25)a) f(x)= 10(x - 1)(x - 5)/[(- 1)(- 5)] = 2(x - 1)(x - 5)b) f(x)= 2x² - 12x+ 10 = (√2 x -3√2)² - 8; √2 p - 3√2 = 0, p = 3; q = - 8; b) r = 2(6- 1)(6 - 5) = 10c) i) g(x)= [(- 8 - 10)/(3 - 6)²](x -6)² + 10 = - 2(x - 6)² + 10c) ii) Let Q = (a, b);c) ii) (a -6)² + (b - 10)² = (6 - 3)² + (10 + 8)² = 333 --- (i)c) ii) b = - 2(a - 6)² + 10 ---(ii)c) ii) Sub.(ii) into (i), (a - 6)² + [- 2(a- 6)² + 10- 10]² = 333c) ii) ⇒ 4(a - 6)⁴ + (a - 6)² - 333 = 0 ⇒ [(a - 6)² - 9][4(a - 6)² + 37] = 0c) ii) ⇒ (a - 6)² = 9 or - 37/4 (rej.) ⇒ a - 6 = ± 3 ⇒ a = 3 (rej.)or 9c) ii) Sub.a = 9 into (ii), b = - 2(9 - 6)² + 10= - 8c) ii)∴ Q = (9, - 8)c) ii) ∵ Mǫʀ = (- 8 - 10)/(9 - 6) = - 6 = (- 8 - 10)/(0 - 3) = Mᴘᴄc) ii)∴ QR // PC 26)a) Let A= (a, 0); (2 - 0)/(6 - a) = 1 ⇒ a = 4; ∴ A = (4, 0)b) Let B = (b, 0); (6- 4)² + 2² = (b - 6)² + 2² ⇒ b = 4(rej.) or 8; ∴ B = (8, 0)c) Equation of BP isy = - 2/(8 - 6) x + 8 ⇒ y = 8 - xd) i) OA = 4 =8 - 4 = ABd) ii) Let C = (0, c), c = 8 - 0 = 8d) ii) A∆ᴏᴀᴄ : A∆ᴀᴘᴄ : A∆ᴀʙᴘ = 4 × 8 : 4 × 8 - 4 × 2 : 4× 2 = 4 : 3 : 1 I HOPE THIS CAN HELPYOU!PLEASE FEEL FREE TO ASKAGAIN IF YOU STILL HAVE ANYPROBLEM!~ ^_^
2012-07-20 23:02:53 補充:
Wong's Q22 c) answer is wrong (and no need calculus!).