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謝謝幫忙
簡單方程式
2012-07-18 3:02 am
回答 (3)
2012-07-18 2:17 pm
✔ 最佳答案
-a(-b/2a)^2=-a[(-b)^2/(2a)^2
=-a[(b^2)/(4a^2)]
=-(b^2)/(4a)
2012-07-18 11:54 pm
-a(-b/2a)^2
=-a(b^2/4a^2)
=-ab^2/4a^2
=-b^2/4a
=-a(b^2/4a^2)
=-ab^2/4a^2
=-b^2/4a
2012-07-18 3:42 am
-a(-b/2a)^2
=-a(b^2/4a^2)
=-b^2/4a
=-a(b^2/4a^2)
=-b^2/4a
收錄日期: 2021-04-16 14:41:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120717000051KK00610