Solve the differential equation analytically.
(dy/dx) = (y)(x)(tanx) and y(0) = 1
Given: y(0) =1, i.e. y = 1 when x = 0
Differential Equation
2012-07-16 8:18 pm
回答 (3)
2012-07-19 2:31 pm
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my maths knowledge
2012-07-17 7:38 am
冇打錯
(dy/dx) = (y)(x)(tanx) and y(0) = 1
Given: y(0) =1, i.e. y = 1 when x = 0
(dy/dx) = (y)(x)(tanx) and y(0) = 1
Given: y(0) =1, i.e. y = 1 when x = 0
2012-07-16 9:24 pm
冇打錯?
基本上係separation of variables,但係integrate x tan(x) 會好複雜。
dy/y = x tan(x) dx
ln |y| = integrate(x tan(x))
y = e^integrate(x tan(x))
但係唔係analytical form,因為x tan(x) integrate唔到
基本上係separation of variables,但係integrate x tan(x) 會好複雜。
dy/y = x tan(x) dx
ln |y| = integrate(x tan(x))
y = e^integrate(x tan(x))
但係唔係analytical form,因為x tan(x) integrate唔到
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