How to find the arbitrary constant in an integral?

2012-07-08 12:50 pm

回答 (4)

2012-07-08 12:52 pm
I guess you dont know what the word "arbitrary" means, then? Its precisely why we use a big C variable as opposed to some numeric value.
2012-07-08 12:56 pm
You need an initial condition. Let's say you have f(x) = x^2 and you want to know what the anti derivative of x^2 is for a certain initial condition. Let's say our initial condition is f'(0)=5. So when you evaluate the antiderivative at x=0 we know the AD is 5. Now... carry out the operation.
Integral: x^2 dx = (x^3)/3 + C. Now... f'(0)=5 so (0^3)/3 + C = 5 and that means C=5. So if you had a problem that said: f(x)=x^2 with f'(0)= 5... what is the arbitrary constant of integration... this is how you'd solved that problem. :) But... without an initial condition.. there's no way to determine it. :)
2012-07-08 12:55 pm
It depends of what is given in the question.
for example if you've found that the integral of a certain function is x² +3x³ +c
and in the question they give y(0)=1 , then you just put x=0 and equal it to 1:

0²+3*0³ +c =1

c=1
2012-07-08 12:54 pm
If you have just integrated and are trying to find the constant 'c'. You need to have a solution to the equation prior.

If the integral only includes x and y, you should be given a co-ordinate (x=X,y=Y). Now input X and Y into the equation and solve to find the constant 'c'.
參考: Degree in Maths


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