logarithm
回答 (2)
2012-07-07 5:59 am
✔ 最佳答案
= log 24^⅓ + log 120^⅓ - log 3^⅓ - log 8^⅓ - log 12^⅓= ⅓log 24 + ⅓log 120 - ⅓log 3 - ⅓log 8 - ⅓log 12= ⅓log(24 × 120/3/8/12)= ⅓log10= ⅓ I HOPE THIS CAN HELP YOU! ^_^
參考: My Maths World
2012-07-08 8:27 am
log24^1/3 + log120^1/3 - log3^1/3 - log8^1/3 - log12^1/3
=(1/3)(log24)+(1/3)(log120)-(1/3)(log3)-(1/3)(log8)-(1/3)(log120)
=(1/3)[log(24*120/3/8/120)]
=(1/3)(log10)
=1/3
=(1/3)(log24)+(1/3)(log120)-(1/3)(log3)-(1/3)(log8)-(1/3)(log120)
=(1/3)[log(24*120/3/8/120)]
=(1/3)(log10)
=1/3
收錄日期: 2021-04-13 18:48:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120706000051KK00689