a以x.y表示z
b當x=4 z=216 求y
更新1:
仲有一題不等式 解2+x/3>11-x/2
變分＼正變
回答 (2)
2012-07-05 3:51 am
✔ 最佳答案
1 (a) 令z = Cy^2/x代入x=6 y=3 z=54
54 = 9C/6
C = 36
因此﹐z = 36y^2/x
(b) x=4 z=216, 216 = 36y^2/4 =>y = √24
2
2 + x/3 > 11 - x/2
5x/6 > 9
x > 54/5
2012-07-07 3:14 am
1a
z=k(y^2)/x k為非零常數
54=k(3^2)/6
k=36
z=36(y^2)/x
1b
216=36(y^2)/4
y^2=24
y=√24
2
2+x/3>11-x/2
12+2x>66-3x
5x>54
x>10.8
z=k(y^2)/x k為非零常數
54=k(3^2)/6
k=36
z=36(y^2)/x
1b
216=36(y^2)/4
y^2=24
y=√24
2
2+x/3>11-x/2
12+2x>66-3x
5x>54
x>10.8
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