are these lines parallel, perpendicular or neither?

1) -8 is the negative reciprocal of 1/8 so the lines are perpendicular.

2) x + y = 4
y = -x + 4
Both lines have a slope of -1. Since their slopes are equal, the lines are parallel.

The first one is perpendicular since 1/8 is the negative reciprocal of -8. The second one is parallel because x + y = 4 can be rewritten as y = -x + 4 so it has the same slope as y = -x.

1) Perpendicular (Slope of second is the negative inverse of the first)

2) Parallel (Slope of second is identical to first)

First, you want to placed the lines in slope-intercept style, it truly is y = mx + b the position m is the slope and b is the y-intercept. x = (–17/11)y + (219/11) 11x = –17y + 219 11x + 17y = 219 17y = –11x + 219 y = (–11/17)x + (219/17) 17x + 11y = 33 11y = –17x + 33 y = (–17/11)x + 3 Parallel lines have the same slope yet diverse y-intercepts...the slope isn't the same, so as that they are not parallel lines. Perpendicular line have slopes that are adverse reciprocals of one yet another...those are in simple terms reciprocals of one yet another, yet not adverse reciprocals of one yet another. So the answer is neither.

Take a look at their slopes.

If the slopes are equal, they are parallel.

If one is a negative reciprocal of the other, they are perpendicular. (in other words, m1 = -1/m2)

If none of the two above are satisfied, they are neither.

Yes