simplify (sinθ+cosθ)^2
how to do???
simplify (sinθ+cosθ)^2
2012-07-04 2:25 am
回答 (6)
2012-07-04 2:44 am
✔ 最佳答案
(sinθ+cosθ)^2=(sinθ)^2+(cosθ)^2+2sinθcosθ
=1+2sinθcosθ
2012-07-13 2:50 am
(sinθ+cosθ)^2
=(sinθ)^2 +2sinθcosθ +(cosθ)^2
=[(sinθ)^2 +(cosθ)^2]+sin(2θ)
=1 +sin(2θ)
=(sinθ)^2 +2sinθcosθ +(cosθ)^2
=[(sinθ)^2 +(cosθ)^2]+sin(2θ)
=1 +sin(2θ)
2012-07-06 8:43 pm
(sinθ+cosθ)^2
=sin^2θ+2sinθcosθ+cos^2θ
=2sinθcosθ+1
=sin^2θ+2sinθcosθ+cos^2θ
=2sinθcosθ+1
2012-07-05 4:04 am
(sinθ+cosθ)^2
=sinθ^2 + cosθ^2 +2(sinθ)(cosθ)
=1+2sinθcosθ
=sinθ^2 + cosθ^2 +2(sinθ)(cosθ)
=1+2sinθcosθ
2012-07-04 6:32 am
sinθ^2 + cosθ^2 = 1
(a+b)^2 = a^2 + b^2 +2ab
所以問題:
(sinθ+cosθ)^2
=sinθ^2 + cosθ^2 +2*sinθ*cosθ
=1+2sinθcosθ
(a+b)^2 = a^2 + b^2 +2ab
所以問題:
(sinθ+cosθ)^2
=sinθ^2 + cosθ^2 +2*sinθ*cosθ
=1+2sinθcosθ
2012-07-04 3:56 am
(sinθ+cosθ)^2
=(sinθ)^2+(cosθ)^2+2sinθcosθ
=1+sin(2θ)
=(sinθ)^2+(cosθ)^2+2sinθcosθ
=1+sin(2θ)
收錄日期: 2021-04-13 18:47:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120703000051KK00450