About Equation of Straight Lin

Slope of L1 is 2/3, slope of L2 is k/6.
As they have one point of intersection, ie, slopes are not the same.
2/3 =/= k/6
==> k =/= 4
And k is a positive integer less than 7, therefore
The possible values of k are 1, 2, 3, 5 and 6.

3y-2x-5=0 ..... (1)
kx-6y+1=0 .... (2)

(1)*2+(2): kx-4x-9=0
(k-4)x=9
x=9/(k-4)
so k can't be 4

as k is a positive integer less than 7
so k could be 1,2,3,5,6

L1: 3y - 2x - 5 = 0

L2: kx - 6y + 1 = 0

From L1: x = (3y - 5)/2

From L2: x = (6y - 1)/k

So, (3y - 5)/2 = (6y - 1)/k

12y - 2 = 3ky - 5k

y = (5k - 2)/(3k - 12)

So, k can not be equal to 4 as 3k - 12 = 0

Possible values of k are 1,2,3,5,6