Two straight lines L1 and L2 are given below:
L1:3y-2x-5=0
L2:kx-6y+1=0 (where constant k is a positive integer less than 7)
If they have one point of intersection, find all possible values of k .
About Equation of Straight Lin
2012-07-02 7:09 pm
回答 (3)
2012-07-04 10:44 pm
✔ 最佳答案
Slope of L1 is 2/3, slope of L2 is k/6.As they have one point of intersection, ie, slopes are not the same.
2/3 =/= k/6
==> k =/= 4
And k is a positive integer less than 7, therefore
The possible values of k are 1, 2, 3, 5 and 6.
2012-07-03 4:54 am
3y-2x-5=0 ..... (1)
kx-6y+1=0 .... (2)
(1)*2+(2): kx-4x-9=0
(k-4)x=9
x=9/(k-4)
so k can't be 4
as k is a positive integer less than 7
so k could be 1,2,3,5,6
kx-6y+1=0 .... (2)
(1)*2+(2): kx-4x-9=0
(k-4)x=9
x=9/(k-4)
so k can't be 4
as k is a positive integer less than 7
so k could be 1,2,3,5,6
參考: myself
2012-07-02 7:24 pm
L1: 3y - 2x - 5 = 0
L2: kx - 6y + 1 = 0
From L1: x = (3y - 5)/2
From L2: x = (6y - 1)/k
So, (3y - 5)/2 = (6y - 1)/k
12y - 2 = 3ky - 5k
y = (5k - 2)/(3k - 12)
So, k can not be equal to 4 as 3k - 12 = 0
Possible values of k are 1,2,3,5,6
L2: kx - 6y + 1 = 0
From L1: x = (3y - 5)/2
From L2: x = (6y - 1)/k
So, (3y - 5)/2 = (6y - 1)/k
12y - 2 = 3ky - 5k
y = (5k - 2)/(3k - 12)
So, k can not be equal to 4 as 3k - 12 = 0
Possible values of k are 1,2,3,5,6
收錄日期: 2021-04-13 18:47:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120702000051KK00158