微積分積分的問題

2012-07-02 7:45 pm
求∫ 2/x^2 -1 dx

回答 (2)

2012-07-02 8:48 pm
是 ∫ 2/(x^2 -1) dx ?

2012-07-02 13:25:09 補充:
∫2/(x^2 - 1)
= ∫[1/(x - 1) - 1/(x + 1)]dx
= ln|x - 1| - ln|x + 1| + C
= ln|(x - 1)/(x + 1)| + C
= - 2atanh x + C


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