微積分積分的問題
回答 (2)
是 ∫ 2/(x^2 -1) dx ?
2012-07-02 13:25:09 補充:
∫2/(x^2 - 1)
= ∫[1/(x - 1) - 1/(x + 1)]dx
= ln|x - 1| - ln|x + 1| + C
= ln|(x - 1)/(x + 1)| + C
= - 2atanh x + C
收錄日期: 2021-04-13 18:47:17
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