中三數~快~要式~(根式)~(40分)~!!!

(√13/4)+(√13/3)
(3√13/12)+(4√13/12) 通分
7√13/12

2012-06-09 16:33:22 補充：
4/(√13/4)+(√13/3)
4×(4/√13)+(√13/3)
(16/√13)+(√13/3)
(16×√13)/(√13×√13)+(√13/3)
(16√13/13)+(√13/3)
(3×16√13/13×3)+(13×√13/3×13)
48√13/39+13√13/39
61√13/39

2012-06-09 16:42:39 補充：
4/√(13/4)+√(13/3)
=4/〔√(13)/√(4)〕+√(13)/√(3)
=4/〔√(13)/2〕+√(13)/√(3)
=4×〔2/√(13)〕+√(13)/√(3)
=8/√(13)+√(13)/√(3)
=8√(13)/13+√(13)√(3)/3
=8√(13)/13+√(39)/3

2012-06-09 16:46:39 補充：
我都5明你表達的式.
√(2/3)≠(√2/3)
√(2/3)=√(2)/√(3)
(√2/3)=√(2)/3

2012-06-09 16:50:45 補充：
√(13/3)都不可

no way to get a sqrt(3) as ans- -.....

Can you type the Q more clearly?

2012-06-09 13:47:40 補充：
(4/(√13/4))+(√13/3)

or

4/((√13/4)+(√13/3))

??

2012-06-09 13:48:19 補充：
Neither of these = 16√3/13 !

2012-06-09 14:51:04 補充：
Maybe he mean √(13/3) ?