In a charity show, a car "flies" from the roof of one building to another building which is 10m lower.
If the initial velocity of the car is 25ms^-1 in the horizontal direction ,what is the maximum distance between the buildings below which the car can land safety?
A.10m
B.25m
C.35m
D.50m
give me a full solution ,please~~~~T^T
F.4 physics projectile motion
2012-06-03 5:43 am
回答 (1)
2012-06-03 6:11 am
✔ 最佳答案
It is quite easy=]First,you need to calculate the vertical direction:
Sy=(1/2)at^2
10=(1/2)gt^2
10=(1/2)X10Xt^2
t^2=2
t=1.4142s
In the horizontal direction:
Sx=ut
Sx=25X1.4142
Sx=35.355m
Sx=35m
Thus,the answer is C (35m)
參考: me
收錄日期: 2021-04-13 18:43:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120602000051KK00593