Solve the following for x, where 0 < x < 2pi
2 tan x + sqrt12 = 0
Please show your work
Help solve the following?
2012-05-27 4:59 pm
回答 (2)
2012-05-27 5:05 pm
✔ 最佳答案
2tanx=-sqrt 12 tanx=(-sqrt 12)/2
x=tan inverse (-sqrt 12)/2
x=-pi/3, 2pi/3, 5pi/3
so x=2pi/3 and 5pi/3
Note in tanx, add pi or minus pi to find the right quardrant.
Hope it helps and good luck.
2012-05-28 12:08 am
I hope this helps -- http://bit.ly/LIdnxD
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