i have an algebra question?
2012-05-27 3:27 pm
us the method of substitution to solve the system of linear equations 4x-y = 3and 9x-2y=10
回答 (6)
2012-05-27 3:53 pm
✔ 最佳答案
4x-y=3 (i)9x-2y=10 (ii)
now from (i) get the value of either x or y
i take the value of x here
4x=3 + y
=>x=(3 + y)/4
now,put the value of x in (ii)
9(3 + y)/4 - 2y=10
=>(27 + 9y)/4 - 2y=10
=>(27 + 9y - 8y)/4=10
=>27 + y=10(4)
=>27 + y=40
=>y=40 - 27
=>y=13
now put the value of y in any equation
i put it in (i)
4x - (13)=3
=>4x - 13=3
=>4x=3 + 13
=>4x =16
=>x=16/4
=>x=4
therefore
x=4
y=13
2016-10-19 4:23 pm
For increasing cubic binomials the final formulation is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D
2012-05-27 3:51 pm
Let 4x-y=3 be equation number 1& 9x-2y=10 be equation number 2
from 1 we get 4x=3+y
=>y=4x-3 ................(eq^n3)
substituting this value in 2 we get
9x-2(4x-3)=10
=>9x-8x+6=10
=>x=10-6=4
=>x=4
substituting the value of x to get y in3
y=4(4)-3=16-3=13
from 1 we get 4x=3+y
=>y=4x-3 ................(eq^n3)
substituting this value in 2 we get
9x-2(4x-3)=10
=>9x-8x+6=10
=>x=10-6=4
=>x=4
substituting the value of x to get y in3
y=4(4)-3=16-3=13
2012-05-27 3:34 pm
4x - y = 3 equation 1
9x - 2y = 10 equation 2
Solve for y in equation 1:
4x - 3 = y
Plug this into equation 2:
9x - 2(4x - 3) = 10
Solve for x:
9x - 8x + 6 = 10
x + 6 = 10
x = 4
Plug this into equation 1 to solve for y:
4(4) - y = 3
16 - y = 3
16 - 3 = y
13 = y
9x - 2y = 10 equation 2
Solve for y in equation 1:
4x - 3 = y
Plug this into equation 2:
9x - 2(4x - 3) = 10
Solve for x:
9x - 8x + 6 = 10
x + 6 = 10
x = 4
Plug this into equation 1 to solve for y:
4(4) - y = 3
16 - y = 3
16 - 3 = y
13 = y
2012-05-27 3:32 pm
These questions are so fun and easy!
Let's see if i can remember from last year.
y= 4x-3
9x-2(4x-3)=10
9x-8x+6=10
x+6=10
x=4
y=4(4)-3
y=16-3
y=13
y=13
x=4
(4,13)
It's not really that hard! Also, you should do them by yourself
Edit: The guy above me did it wrong he forgot to change to - to a + when multiplying a - and a -.
So it screwed the whole problem.
Let's see if i can remember from last year.
y= 4x-3
9x-2(4x-3)=10
9x-8x+6=10
x+6=10
x=4
y=4(4)-3
y=16-3
y=13
y=13
x=4
(4,13)
It's not really that hard! Also, you should do them by yourself
Edit: The guy above me did it wrong he forgot to change to - to a + when multiplying a - and a -.
So it screwed the whole problem.
參考: School
2012-05-27 3:32 pm
Let y=4x-3
Substitute y=4x-3 into 9x-2y=10
9x-2(4x-3)=10
solved x=-4
Substitute x=-4 to y=4x-3
solved y=-19
So x=-4 and y=-19
Hope it helps
Sorry, my bad, answer should be x=4, y=13.
Substitute y=4x-3 into 9x-2y=10
9x-2(4x-3)=10
solved x=-4
Substitute x=-4 to y=4x-3
solved y=-19
So x=-4 and y=-19
Hope it helps
Sorry, my bad, answer should be x=4, y=13.
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