find the product (3p + 4 )( 2p^3 – 5p + 6)?

expand the brackets using an extended method of FOIL.

= 6p^4 - 15p^2 + 18p + 8p^3 - 20p + 24
= 6p^4 + 8p^3 - 15p^2 -2p + 24

to locate p: 3p+4=5p-6+p -4 -4 <cancel the 4 variety the left section and subtract from the 6 3p=5p-10+p Simplify the perfect section. =>3p=6p-10 3p=6p-10 -6p -6p <subtract 6p to cancel the the 6p on the perfect section and subtract 6p from the 3p section. -3p=10 divide the ten by -3 to locate the answer to p for this reason p= -10/3

( 3p + 4 ) ( 2p^3 - 5p + 6 )
= 6p^4 - 15p^2 + 18p + 8p^3 - 20p + 24
= 6p^4 + 8p^3 - 15p^2 - 2p + 24

1) 6p^4+8p^3-15p^2-2p+24