數學知識交流 - 求值

2012-05-27 7:03 pm
若 x³- (3√2)x²+ 6x - 2√2 - 8 = 0,求 x⁵- 41x²+ 2012 的值。

回答 (2)

2012-05-28 12:43 am
✔ 最佳答案
x³ - (3√2)x² + 6x - 2√2 - 8 = 0
(x - √2)³ - 8 = 0
實根 x = 2 + √2
x² = 6 + 4√2
x⁴= 68 + 48√2
x⁵ = (68 + 48√2)(2 + √2) = 232 + 164√2
∴ x⁵ - 41x² + 2012
= 232 + 164√2 - 41(6 + 4√2) + 2012
= 1998
2012-05-28 3:58 am
Should complex solutions be included?


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