6a^2-a-1
12y^2+7y+1
18-7m-m^2
6p^2+p-35
thanks!!!
please help me factor trinomials to binomials?
2012-05-27 1:42 am
回答 (3)
2012-05-27 1:51 am
✔ 最佳答案
1) (3a+1)(2a-1)2) (3y+1)(4y+1)
3)(-m-9)(m-2)
4)(3p+5)(2p-3)
Sorry my fault, 4) should be (3p-7)(2p+5) as the one below said.
2012-05-27 8:56 am
6a^2-a-1 ---> (3a +1 )(2a- 1)
12y^2+7y+1 ---> (3y + 1)( 4y + 1)
18-7m-m^2 = -m^2 - 7m+ 18 = - (m^2+ 7m -18) = -(m+9)(m-2)
6p^2+p-35 ---> (3p-7)(2p+5)
12y^2+7y+1 ---> (3y + 1)( 4y + 1)
18-7m-m^2 = -m^2 - 7m+ 18 = - (m^2+ 7m -18) = -(m+9)(m-2)
6p^2+p-35 ---> (3p-7)(2p+5)
參考: Geometry student, and got an A in Algebra
2012-05-27 8:56 am
(3a + 1)(2a - 1)
(4y + 1)(3y + 1)
-(m^2 + 7m - 18)
-(m + 9)(m - 2)
6p^2 + p - 35
(p + 5/2)(p - 7/3)
(4y + 1)(3y + 1)
-(m^2 + 7m - 18)
-(m + 9)(m - 2)
6p^2 + p - 35
(p + 5/2)(p - 7/3)
收錄日期: 2021-05-01 15:53:57
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