畢氏定理 & 三角比- 中二數學

2012-05-27 12:16 am

回答 (1)

2012-05-29 4:21 am
✔ 最佳答案
1)
AF² = (5+3+1)² + (4 - 2)²
AF = √85


2a)
x² + x² = y²
x² = y²/2
x = y/√2

b)
x = 5/√2 = 3.54(準確至兩個小數位)


3)
tan θ
= m²n(m+n) / mn²
= m(m+n) / n


4)
cos θ = x / b
x = b cos θ


5)
cos φ / sin θ
= (c/a) / (c/a)
= 1


6)
設斜線為 y ,
1/y = cos φ ... (1)
{
x/y = sin θ ... (2)

(2) / (1) :
x = sinθ / cosφ


7)
設底邊為 y ,
x / y = tanθ ... (1)
{
y / a = cos(θ + φ) ... (2)

(1) * (2) :
x / a = tanθ cos(θ + φ)
x = a tanθ cos(θ + φ)


收錄日期: 2021-04-21 22:31:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120526000051KK00368

檢視 Wayback Machine 備份