數學知識交流 － 平分角
回答 (3)
2012-05-26 4:35 am
✔ 最佳答案
圖片參考：http://imgcld.yimg.com/8/n/HA00016323/o/701205250045613873409080.jpg
http://i1099.photobucket.com/albums/g395/jasoncube/cd77fc6c.png ∵ DP = PE & D, P, E arecollinear∴ Area of ∆DBP = Areaof ∆ EBP½(BD)(BP)sin∠DBP = ½(BE)(BP)sin∠EBPBDsin∠ABP = BEsin∠CBP∵ BD may not = BE∴ sin∠ABP may not = sin∠CBPi.e.∠ABP may not = ∠CBP, the ans is NO.
參考: My Maths World
2012-05-27 2:05 am
pls refer to the below diagram:
圖片參考：http://imgcld.yimg.com/8/n/HA08446686/o/701205250045613873409090.jpg
2012-05-26 18:12:59 補充：
In general, PB bisects ∠ABC if and only if BD=BE.
That is, in an isoscels triangle, the median of the base is the bisector of the vertical angle.
圖片參考：http://imgcld.yimg.com/8/n/HA08446686/o/701205250045613873409090.jpg
2012-05-26 18:12:59 補充：
In general, PB bisects ∠ABC if and only if BD=BE.
That is, in an isoscels triangle, the median of the base is the bisector of the vertical angle.
2012-05-26 4:07 am
我想, 答案為 "不"
若∠ABC為直角，
及∠ABP = ∠CBP ( =45' )
則DE的斜率必須為若干數值(與BP互相垂直)
若DE和BP不是互相垂直，
在這情況下，則∠ABP 不等於∠CBP
如有錯漏，請務必指正 :)
若∠ABC為直角，
及∠ABP = ∠CBP ( =45' )
則DE的斜率必須為若干數值(與BP互相垂直)
若DE和BP不是互相垂直，
在這情況下，則∠ABP 不等於∠CBP
如有錯漏，請務必指正 :)
收錄日期: 2021-04-13 18:42:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120525000051KK00456