The essence of the question is asking the formula for all factors 8 instruments from (-2,3). the final formula for a circle is r^2 = (x-a)^2 + (y-b)^2 In that formula, the midsection of the circle is placed at (a,b) putting interior the numbers out of your mission 8^2 = (x -(-2))^2 + (y - 3)^2 sixty 4 = (x+2)^2 + (y -3)^2 yet you actually have the actual undeniable reality that x= - y .substitute that again into the line above this one and also you've gotten a formula in only one variable that you will be able to sparkling up for the answer.
There should be 2 numbers after the decimal point. Suppose you have 2.4321 then the answer would be 2.43 and if the third digit is 5 or more such as 1.456 then it would be 1.46. The last digit is increased by 1 in such cases.
Whatever the solution to your math problem is, just round the number so it only has two numbers after the decimal point.
EXAMPLE: If the answer is 1.87456, then you would round it to 1.87
Suppose your solution is x=4.362
The first two decimal places are 3 and 6 and x rounds to 2.62 to 2 decimal points.
If the 3rd decimal is 5 or more , say 4.367 it rounds up to 4.37
For example, type pi in your calculator, you get 3.141592654 round up to 2 decimal places, would be
3.14 because if you see value from 0-4 you can ignore the number after two decimal places.
If you see value from 5-9 you round up the answer. E.g 5.656789 round up to 2 d.p would be 5.66
It should read "Round your solution TO two decimal places" This means that if your solution has a decimal fraction, you round it to two places. If the third digit in the decimal fraction is less than 5, truncate, i.e., cut off the fraction after the second place. If the 3rd digit is equal to or greater than 5, "round up" the second digit by 1.