Solve (2xy+y^2)dy + y^2dx=0 Given initial condition y(1)=2
I tried and got a solution y^2(3x+y)=20 but I don't know if it is correct. Please give it a try and see if you could get the same solution as me. Thanks
收錄日期: 2021-05-01 15:56:45
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https://hk.answers.yahoo.com/question/index?qid=20120521142016AAmDGvm