Trigonometric radio.
回答 (3)
1/cos(90-Θ)-sin(90-Θ)/tanΘ
=1/sinΘ-cosΘ/tanΘ
=1/sinΘ-cos^2Θ/sinΘ
=sin^2Θ/sinΘ
=sinΘ
cos(90 - Θ)=sinΘ
sin (90 - Θ)=cosΘ
tanΘ=sinΘ/cosΘ
1/cos(90 - Θ) - sin(90 - Θ)/tanΘ
= 1/sinΘ - cosΘ/tanΘ
= 1/sinΘ - cos Θ÷sinΘ/cosΘ
=1/sinΘ - cos ΘxcosΘ/sinΘ
=1/sinΘ - cos Θ^2/sinΘ
= (1 - cos^2 Θ)/sinΘ
= sin^2 Θ/sinΘ
= sinΘ
參考: me
1/cos(90 - Θ) - sin(90 - Θ)/tanΘ
= 1/sinΘ - cosΘ/tanΘ
= 1/sinΘ - cos^2 Θ/sinΘ
= (1 - cos^2 Θ)/sinΘ
= sin^2 Θ/sinΘ
= sinΘ
收錄日期: 2021-04-26 19:17:34
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https://hk.answers.yahoo.com/question/index?qid=20120517000051KK00658
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