DSE MATHS
回答 (2)
2012-05-14 4:29 am
✔ 最佳答案
(x-a)(x-a-1)=(x-a)(x-a)(x-a-1)-(x-a)=0
(x-a)(x-a-1-1)=0
(x-a)(x-a-2)=0
x-a=0 or x-a-2=0
x=a or x=a+2
參考: me
2012-05-14 3:48 am
(x-a)(x-a-1)=(x-a)
(x-a)(x-a-1) -(x-a) = 0
(x-a)(x-a-1-1) = 0
(x-a) = 0 or (x-a-1) = 0
x=a or x=a+1
(x-a)(x-a-1) -(x-a) = 0
(x-a)(x-a-1-1) = 0
(x-a) = 0 or (x-a-1) = 0
x=a or x=a+1
參考: me
收錄日期: 2021-04-20 12:46:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120513000051KK00626