更新1:
[URL=http://upload.lyfhk.net/pm-1STP.html][IMG]http://upload.lyfhk.net/di-1STP.jpg[/IMG][/URL]
更新2:
http://upload.lyfhk.net/di-1STP.jpg
physic 難題 14
回答 (1)
2012-05-07 7:33 pm
✔ 最佳答案
(a) The node equation is:(24-V)/28 + (12-V)/12 = V/16
where V is the potential at the right-hand side of the 16-ohm resistor, and assume the -ve terminals of the two batteries are at potential of 0 v.
(b) Solving the node equation for V gives V = 10.098 v
Hence, I1 = (24-10.098)/28A = 0.4965 A
I2 = (12-10.098)/12 A = 0.1585 A
I3 = 10.098/16 A = 0.6311 A
收錄日期: 2021-04-29 17:47:15
原文連結 [永久失效]:
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