Prove the following trigonometric identities.
4sin^2 θ-3 ≡ 1 - 4sin^2 (90°- θ )
please shows your step .. thanks!
F.2 maths:trigonometric ratios
2012-05-06 4:23 am
回答 (1)
2012-05-06 4:34 am
✔ 最佳答案
R.H.S.= 4sin²θ - 3= 1 + 4sin²θ - 4= 1 + 4sin²θ - 4(sin²θ + cos²θ)= 1 - 4cos²θ= 1 - 4sin²(90°- θ )= L.H.S.
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