Cr2O7 2- + 14H+ + 6e- ------------> 2Cr3+ + 7H2O
For this half equation shown above, Cr2O7 undergoes reduction as the oxidation number decreases. So, which substances in the above undergoes oxdiation?
redox reaction problem
2012-05-05 2:03 am
回答 (1)
2012-05-05 2:25 am
✔ 最佳答案
NONE. As you've mentioned, this is only a half equation, which actually shows the reduction of dichromate; the substrate for oxidation depends on what it's reacting with.
Also, note your wordings: oxidation number of chromium (in dichromate) decreases, so there's reduction.
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