✔ 最佳答案
1d) With sin θ/tan θ = cos θ, it will be <0 for quadrants 2 and 3.
e) With tan θ/cos θ = sin θ/cos2 θ, it will be > 0 for quadrants 1 and 2 (sin θ > 0 since cos2 θ > 0 for all θ except 90 and 270)
f) cos θ sin θ < 0 if:
sin θ < 0 and cos θ > 0 (quadrant 4) OR
sin θ > 0 and cos θ < 0 (quadrant 2)
5a) cos 300 = cos (360 - 60) = cos 60 = 1/2
b) tan (-225) = - tan 225 = - tan (180 + 45) = - tan 45 = -1
c) tan 210 = tan (180 + 30) = tan 30 = (√3)/3
d) sin 135 = sin (180 - 45) = sin 45 = (√2)/2
11) tan θ = -20/21 and sin θ < 0, hence cos θ > 0
Thus
sin θ = - 20/√(202 + 212) = -20/29
cos θ = 21/√(202 + 212) = 21/29