高中化學1題(急需)
回答 (1)
2012-05-02 11:24 am
✔ 最佳答案
設加入 m 克的 NH4Cl。[NH3]o = 0.2 M
[NH4Cl]o = [m/(14 + 1x4 + 35.5)]/5 = m/267.5 M
NH3(aq) + H2O(l) ⇌ NH4^+(aq) +OH^-(aq)
平衡時：
[NH3] = 0.2 M - (1.0 x 10^-5) ≈ 0.2 M
[NH4^+] = (m/267.5) + (1.0 x 10^-5) = m/267.5 M
Kb = [NH4^+][OH^-]/[NH3]
(m/267.5)(1.0 x 10^-5)/(0.2) = 1.6 x 10^-5
m = 85.6
所加入 NH4Cl 的質量 = 65.6 g
參考: fooks
收錄日期: 2021-04-13 18:40:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120502000015KK00664