polynomial

你會唔會出錯題呢？
應該係Q(x-1) must be divisible by x
or ???

若如我如上估計的問題，則其解如下：

Q(x) divisible by x + 1
according to remainder thm,
Q(-1) = 0
Let g(x) = Q(x-1)
If g(x) divided by x
According to remainder thm
the remainder will be:
g(0)
to switch back to function Q
g(0) = Q(0-1) = Q(-1)
where Q(-1) = 0 which is given
Therefore Q(x-1) is divisible by x