請詳細步驟教我計以下幾條.(不可用計算機計要有步驟).
(不要綱址回答)
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急 ! Logarithmic Function 9p3
2012-04-22 9:07 am
回答 (2)
2012-04-22 5:37 pm
✔ 最佳答案
110=log8/[log(1/2)]
=3log2/(-log2)
=-3
111
=(log1-log3)/log9
=-log3/2log3
=-1/2
112
=(log1-log8)/(log1-log4)
=-3log2/-2log2
=3/2
113
=(1/2)(log27)/(log1-log3)
=(3log3/2)/-log3
=-3/2
114
=log6/log2
=(log3+log2)/log2
115
=log12/log3
=(log3+log4)/log3
=(log3+2log2)/log3
116
=log30/log5
=(log6+log5)/log5
=(log2+log3+log5)/log5
117
=log42/log7
=(log7+log6)/log7
=(log7+log2+log3)/log7
2012-04-22 9:32 am
110 log1/2_8=log8/log(1/2)=3log2/－log2=－3
111 log9_(1/3)=log(1/3)/log9=－log3/2log3=－1/2
112 log1/4_1/8=log(1/8)/log(1/4)=log8/log4=3/2
113 log1/3_√27=(1/2)*log27/log(1/3)=(1/2)*3log3/－log3=－3/2
114 log2_6=log6/log2=(log2+log3)/log2
115 log3_12=log12/log3=(2log2+log3)/log3
116 log5_30=log30/log5=(log3+1)/(1-log2)
117 log7_42=log42/log7=(log2+log3+log)/log7
111 log9_(1/3)=log(1/3)/log9=－log3/2log3=－1/2
112 log1/4_1/8=log(1/8)/log(1/4)=log8/log4=3/2
113 log1/3_√27=(1/2)*log27/log(1/3)=(1/2)*3log3/－log3=－3/2
114 log2_6=log6/log2=(log2+log3)/log2
115 log3_12=log12/log3=(2log2+log3)/log3
116 log5_30=log30/log5=(log3+1)/(1-log2)
117 log7_42=log42/log7=(log2+log3+log)/log7
收錄日期: 2021-04-13 18:39:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120422000051KK00046