F4 Maths
2012-04-20 6:22 am
8.0g of magnesium are treatedwith 100cm^3 of dilute sulphuric acid containing196g of acid per dm3. Calculate (a) the mass of magnesiumleft (b) the volume of hydrogen produced at room conditions. ANS:a) 3.2 g b) 4.8 dm3
回答 (1)
2012-04-20 7:09 am
✔ 最佳答案
a) No. of moles of H2SO4 = 196 x 0.1/98 = 0.2From the equation:
Mg + H2SO4 -> MgSO4 + H2
1 mole of Mg reacts completely with 1 mole of H2SO4.
Hence, no. of moles of magnesium left = 8/24 - 0.2 = 2/15
with mass = 2/15 x 24 = 3.2 g
b) NO. of moles of H2 produced = 0.2
So vol. = 0.2 x 24 = 4.8 dm3
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