一.有食鹽水100克,含鹽10%,今以含鹽5%的食鹽水若干克混成含鹽7%的食鹽水,求混入的食鹽水幾克? (100x10%+Nx5%)/100+N=7%N為所求的食鹽水.N=150 (答案) 二.純酒8斤混水2斤,每斤3.2元,若每斤售3.6元,於純酒9斤內,當混水若干? 8/(8+2)xN=3.2N=49/(9+Y) xN=3.6Y:為所求的若干水Y=1(答案) 計算方式定還是:2/(8+2)xN=3.2Y/(9+Y) xN=3.6
收錄日期: 2021-04-13 18:38:12
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https://hk.answers.yahoo.com/question/index?qid=20120419000051KK00531