送分題-二次方程

2012-04-15 6:10 pm

回答 (2)

2012-04-15 7:07 pm
✔ 最佳答案
2x^2+x+2=0,find √x in terms of a+bi.
Sol
2x^2+x+2=0
2x^2+x=-2
x^2+x/2=-1
x^2+2*x*(1/4)=-1
x^2+2*x*(1/4)+(1/4)^2=1/16-1
(x+1/4)^2=-15/16
x+1/4=+/-√15/4
x=-1/4+/-√15/4


2012-04-15 7:18 pm
To 001
題目是find √x in terms of a+bi.


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