solve the following simultaneous equations......
p-q+6=0
3p(p/4 +1)-q+4=0
F4 Maths
2012-04-11 2:34 am
回答 (1)
2012-04-11 3:15 am
✔ 最佳答案
p-q+6=0p-q= -6
q-p=6-----(1)
3p(p/4+1)-q+4=
3p^2/4+3p-q= -4 ----(2)
(1)+(2):3p^2/4+2p=2
3/4 p^2+2p-2=0
p= [2±√(2^2-4(3/4)(-2)]/2(3/4)= 2(-2±√10)/3=[-4±2√10]/3
q=6+p=6+(4±2√10)/3=(18+4±2√10)/3=(22±2√10)/3
收錄日期: 2021-04-13 18:37:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120410000051KK00825