Super Easy Math Question

2012-04-11 12:25 am
OABis a triangle, OA = 5, OB = 3, ∠BOA = 40º, find ∠OAB .

回答 (4)

2012-04-11 1:43 am
✔ 最佳答案
By cosine theorem
AB^2=OA^2+OB^2-2(OA)(OB)cos∠OAB
=25+9-2(5)(3)cos40
=34-30cos40
AB=√(34-30cos40)

^為方便計算 先用計算機AnsM+ (確定Clr左Mem)

OB^2=OA^2+AB^2-2(OA)(AB)cos∠OAB
∠OAB=cos^-1[OB^2-OA^2-AB^2/-2(OA)(AB)]
=cos^-1[9-25-34+30cos40 / -2(5)[√(34-30cos40]
=cos^-1[50-30cos40 / 10√(34-30cos40)
=cos^-1[16+34-30cos40/10√(34-30cos40)

用計算機:cos^-1[16+M^2 / 10M]

∠OAB=35.5(corr.to 3sig.fig.)//
2012-04-11 5:24 pm
sine formula + cosine formula

2012-04-13 20:44:26 補充:
Super Easy D.I.Y.
2012-04-11 5:30 am
"不攔路的狗"冇答過就想要20點lo
2012-04-11 1:39 am
Super easy!
Do it yourself and give me 20 pts!


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