Mass, Volume and Keq

2012-04-08 1:53 am

An equilibrium mixture, at 538°C in a 1618-mL container, involving the chemical systemN2(g) + 3H2(g)
圖片參考：https://lewis.chem.sfu.ca/res/sfu/batchelo/Gallery/rlharpoons.gif
2NH3(g)is found to contain 3.30 g of N2, 0.116 g of H2, and 0.0193 g of NH3. Calculate the equilibrium constant (Keq expressed in terms of the molar concentrations) at the given temperature.

Thanks

回答 (1)

[匿名]

2012-04-08 7:16 am

✔ 最佳答案

先計equilibrium既conc.
之後就要sub數就會計到

1618ml = 1618cm^3 = 1.618dm^3

[N2(g)]eqm = (3.30g/(14x2)gmol^-1) / 1.618dm^3 = 0.07284125 M
[H2(g)]eqm = (0.116g/(1x2)gmol^-1) / 1.618dm^3 = 0.035846724 M
一陣會用到[H2(g)]eqm ^3 計埋啦～
[H2(g)]eqm ^3 = 4.606259797x10^-5 M^3
[NH3(g)]eqm = (0.0193g/(14+1x3)gmol^-1) / 1.618dm^3 = 7.016650913x10^-4 M
都係啦
一陣會用到 [NH3(g)]eqm ^2
[NH3(g)]eqm ^2 = 4.923339003X10^-7 M^2

Keq =

[NH3(g)]eqm ^2
------------------------------------ = 0.1467 M^-2
[H2(g)]eqm ^3 [N2(g)]eqm

有錯要指正v_____v
希望幫到你

參考: self: )

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