INTEG [1, -1] (4 / (1+x^2)) dx
what integration would i use for this and how would it be solved?
Can someone guide me through this integration problem?
2012-04-04 1:59 am
回答 (3)
2012-04-04 2:20 am
If the first two answers didn't help here is a little more detail:
substitute x = tan u and note dx/du = 1/cos^2(u) and tan^2(u) = sin^2(u)/cos^2(u) = (1/cos^2(u)) -1.
Your integral becomes:
INTEG[ tan(1), tan(-1) ] ( 4 du )
since dx = cos^2(u) du
Which is easy.
substitute x = tan u and note dx/du = 1/cos^2(u) and tan^2(u) = sin^2(u)/cos^2(u) = (1/cos^2(u)) -1.
Your integral becomes:
INTEG[ tan(1), tan(-1) ] ( 4 du )
since dx = cos^2(u) du
Which is easy.
2012-04-04 2:09 am
trig sub
2012-04-04 2:02 am
Put x = tan @
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