F4 CIRCLE

2012-04-03 1:16 am

圖片參考:http://imgcld.yimg.com/8/n/HA04937267/o/701204020054113873387030.jpg

計左成日都計唔到e條-.-...
搵人幫幫手,thx
更新1:

ps,CIRCLE既prop入面, 淨係比用 chord:(我諗唔會用到= =) line from centre⊥chords bisects chord line from centre to mid-pt. of chord ⊥ chord equal chords,equidistant from centre chords equidistant from centre are equal

更新2:

angle: < in semicircle < at centre twice < at circumference

更新3:

angle: < in semicircle < at centre twice < at circumference

更新4:

converse of < in semicircle

更新5:

同埋

更新6:

angles in the same segment

更新7:

超勁=.=thx

回答 (1)

2012-04-03 1:46 am
✔ 最佳答案
Join PQ , ∠RPQ = ∠RDQ (∠s in the same segment) ...... (1)∠ASQ = ∠RDQ + ∠DQS (ext. ∠ of Δ) ...... (2) ∠ASQ
= ∠APQ (∠s in the same segment)
= ∠APR + ∠RPQ ...... (3)
Substitute (1) into (2) :
∠ASQ = ∠RPQ + ∠DQS ...... (4)
Substitute (3) into (4) :
∠APR + ∠RPQ = ∠RPQ + ∠DQS
∠APR = ∠DQS
∠APR = 180° - ∠SQC (adj. ∠s on st. line)
70° = 180° - ∠SQC
∠SQC = 110°


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