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急!急! Logerithmic Functions 9q5
2012-03-31 8:16 am
回答 (2)
2012-03-31 9:52 am
參考: F4 science student
2012-04-01 1:21 am
16a
(logx+logx^3)/log√x
=logx^4/log√x
16b
=[logx^(5/2)+logx^(3/4)]/[logx^(5/2)-logx^(3/4)]
=[logx^(13/4)]/[logx^(7/4)]
16c
=(logy/3logx)(2logx)/3logy
=(2logy/3)[1/(3logy)]
=2/9
17a
log210
=log3+log7+log10
=p+q+1
17b
log(81/7)
=log81-log7
=4log3-q
=4p-q
17c
=log63/log3
=(log7+2log3)/log3
=(2p+q)/p
(logx+logx^3)/log√x
=logx^4/log√x
16b
=[logx^(5/2)+logx^(3/4)]/[logx^(5/2)-logx^(3/4)]
=[logx^(13/4)]/[logx^(7/4)]
16c
=(logy/3logx)(2logx)/3logy
=(2logy/3)[1/(3logy)]
=2/9
17a
log210
=log3+log7+log10
=p+q+1
17b
log(81/7)
=log81-log7
=4log3-q
=4p-q
17c
=log63/log3
=(log7+2log3)/log3
=(2p+q)/p
收錄日期: 2021-04-13 18:35:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120331000051KK00011